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JavaScript Fundamentals · Working with JSON · Lesson 36 of 48

Parsing JSON with parse

Concept

Parsing JSON with parse

JSON.parse() does the reverse — it turns a JSON string back into a real JavaScript object you can work with, including nested objects and arrays.

Parsing invalid JSON throws a SyntaxError, so real code that parses external data (like an API response) usually wraps JSON.parse in a try/catch.

By the end of this lesson
  • Explain the core idea behind Parsing JSON with parse.
  • Predict output before running a change.
  • Test one realistic and one unusual input.
  • Use the result to make the next decision.
How to study this page
  1. 1. Read one concept.
  2. 2. Change the example.
  3. 3. Run, compare, and explain.
  4. 4. Complete the challenge below.
Syntax
JSON.parse(jsonString)
ExampleRunnable
const json = '{"name":"Alex","skills":["JS","CSS"]}';
const data = JSON.parse(json);
console.log(data.name, data.skills[0]);
Try it Yourself »
Safely parsing with try/catch
try {
  const data = JSON.parse("not valid json");
} catch (error) {
  console.log("Invalid JSON received");
}
Self-check before continuing

Without looking at the example, describe what changes when you modify one input in Parsing JSON with parse. Then reopen the editor and prove your explanation with a small test.

You are ready to continue when you can predict, test, and explain the result.

Your turn

Parse a JSON string containing a nested array, then log one item from that array.

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Console

Output will appear here...